AtmaWeapon
10-01-2002, 07:50 PM
I have a rather odd request.
I took an exam in calculus today. I encountered the problem:
lim 5x*sin(3/x)
x->infinity
It seemed simple at first; 3/x will approach 0 as x approaches infinity. Therefore, sin(3/x) would approach 0 as x approached infinity. Since sin(3/x) evaluated to 0, I decided the correct answer was 0.
HOWEVER, things were not so simple. I plugged the equation into my TI-89, and somehow the calculator got 15 for the answer.
So, who's right, me or the calculator? If it's the calculator, please post an explanation.
I took an exam in calculus today. I encountered the problem:
lim 5x*sin(3/x)
x->infinity
It seemed simple at first; 3/x will approach 0 as x approaches infinity. Therefore, sin(3/x) would approach 0 as x approached infinity. Since sin(3/x) evaluated to 0, I decided the correct answer was 0.
HOWEVER, things were not so simple. I plugged the equation into my TI-89, and somehow the calculator got 15 for the answer.
So, who's right, me or the calculator? If it's the calculator, please post an explanation.